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Determinant

Exercise 1: Simple matrix

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title	Exercise: Simple matrix

Compute the determinant

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title	Solution: Simple matrix

Code Block

language	py
title	Solution: Simple matrix

import numpy as np 

# Defining the matrix
A = np.array([[1, 3, 2],
            [4, 1, 3],
            [2, 5, 2]])

det = np.linalg.det(A)
print(det)


# Output:
16.999999999999993   # e.i. det(A) = 17

Exercise 2: Complex numbers

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title	Exercise: Complex numbers

This example is taken from an example exam in TMA4110 - Calculus 3, check out the exam and the solution for hand calculations (only in norwegain). This is task 4.

Comput the determinant

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title	Solution: Complex numbers

Code Block

language	py
title	Solution: Complex Numbers

import numpy as np 

# Defining the matrix
# Notice how we can define complex numbers in python by adding the letter "j"
# "j" is used to denote an imaginary unit instead of "i", because Python follows engineering,
# where "i" denotes the electric current as a function of time (especially electrial engineering)
A = np.array([[3, 1-1j, 1j, 4],
            [3, 1, 1-2j, 4+7j],
            [6j, 2+2j, -2, 3j],
            [-3, -1+1j, 1, 3-4j]], dtype=complex)

det = np.linalg.det(A)
print(det)


# Output:
(-15-15j)   # e.i. det(A) = -15-15i

Least squares solution to a linear system

Exercise 1

:

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title	Exercise

This example is taken from an example exam in TMA4110 - Calculus 3, check out the exam and the solution for hand calculations (only in norwegain). This is task 5.

Use the least squares method to find an approximation to the linear system

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title	Solution:

First, lets write the equations as matrices on the format

, where

To solve the problem in NumPy, we will use the function numpy.linalg.lstsq (or with SciPys scipy.linalg.lstsq) which is currently not described in Matrices and linear algebra. We recommend you to read the function documentation before proceeding.

Code Block

language	py
title	Solution

import numpy as np 

# Defining the matrices
A = np.array([[1, 2],
            [3, 4],
            [5, 6]])
b = np.array([[1],[2],[3]])

x, residuals, rank, s = np.linalg.lstsq(A, b, rcond=None)   
# "rcond=None" sets new default for rcond, see function documentation

print(x)    # "x" is the solution


# Output:
[[-5.97106181e-17]
 [ 5.00000000e-01]]

We can interpret this such as the least squares solution is

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Determinant

Exercise 1: Simple matrix

Exercise 2: Complex numbers

Least squares solution to a linear system

Exercise 1